This is one of the easiest programs.
An anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.
Given two strings s
and t
, return true
if t
is an anagram of s
, and false
otherwise.
An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.
Example 1:
Input: s = "anagram", t = "nagaram"
Output: true
Example 2:
Input: s = "rat", t = "car"
Output: false
Constraints:
1 <= s.length, t.length <= 5 * 104
s
andt
consist of lowercase English letters.
Follow up: What if the inputs contain Unicode characters? How would you adapt your solution to such a case?
class Solution { public: bool isAnagram(string s, string t) { if (s.length() != t.length()) { return false; } int count[26]; memset(count, 0, sizeof(count)); for (int i = 0; i < s.length(); i++) { count[s[i] - 'a']++; count[t[i] - 'a']--; } for (int cnt : count) { if (cnt != 0) { return false; } } return true; } };
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